## Engineering Mechanics: Statics & Dynamics (14th Edition)

$F=19.6lb$ $F_b=26.4lb$
We are given that the component of force, $F$, acting on line $aa$ is $Fa=30lb$. Using the law of sines with the given angles, we can find the magnitude of F and the component of F on line $bb$. $\sin80^{\circ} / 30lb = \sin 40^{\circ} / F$ Solving for $F$, we obtain: $F=19.6lb$ $\sin80^{\circ} / 30lb = \sin 60^{\circ} / F_b$ Solving for $F_b$, we obtain: $F_b=26.4lb$