Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 2 - Force Vectors - Section 2.3 - Vector Addition of Forces - Problems: 13

Answer

$F_a=30.6lb$ $F_b=26.9lb$

Work Step by Step

We are given that the force acting on the gear tooth is $F=20lb$. Using the law of sines with the given angles, we can resolve the F into it's components. $\sin40^{\circ} / 20lb = \sin 80^{\circ} / F_a$ Solving for $F_a$, we obtain: $F_a=30.6lb$ $\sin40^{\circ} / 20lb = \sin 60^{\circ} / F_b$ Solving for $F_b$, we obtain: $F_b=26.9lb$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.