## Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson

# Chapter 2 - Force Vectors - Section 2.3 - Vector Addition of Forces - Problems - Page 29: 5

#### Answer

$F_{AB}=314lb$ $F_{AC}=256lb$

#### Work Step by Step

We can use the law of sines to find the magnitudes of the components of $F$. $\sin75^{\circ}/350lb=\sin60^{\circ}/F_{AB}$ $F_{AB}=\sin60^{\circ} *350lb/\sin75^{\circ}$ $F_{AB}=314lb$ $\sin75^{\circ}/350lb=\sin45^{\circ}/F_{AC}$ $F_{AC}=\sin45^{\circ} *350lb/\sin75^{\circ}$ $F_{AC}=256lb$

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