Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 2 - Force Vectors - Section 2.3 - Vector Addition of Forces - Problems - Page 29: 4


$F_{AB}=448N$ $F_{AC}=366N$

Work Step by Step

We can use the law of sines to find the magnitudes of the components of $F$. $\sin75^{\circ}/500N=\sin60^{\circ}/F_{AB}$ $F_{AB}=\sin60^{\circ} *500N/\sin75^{\circ}$ $F_{AB}=448N$ $\sin75^{\circ}/500N=\sin45^{\circ}/F_{AC}$ $F_{AC}=\sin45^{\circ} *500N/\sin75^{\circ}$ $F_{AC}=366N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.