Engineering Mechanics: Statics & Dynamics (14th Edition)

$F_{AB}=448N$ $F_{AC}=366N$
We can use the law of sines to find the magnitudes of the components of $F$. $\sin75^{\circ}/500N=\sin60^{\circ}/F_{AB}$ $F_{AB}=\sin60^{\circ} *500N/\sin75^{\circ}$ $F_{AB}=448N$ $\sin75^{\circ}/500N=\sin45^{\circ}/F_{AC}$ $F_{AC}=\sin45^{\circ} *500N/\sin75^{\circ}$ $F_{AC}=366N$