#### Answer

$I_{O}=0.113$ kg*m$^2$

#### Work Step by Step

$m_{circle}=\pi (0.2)^2 (20)=0.8\pi$ kg
$m_{square}=(0.2)^2 (20)=0.8$ kg
$I_{O}=\Sigma I_{G}+md^2=(\frac{1}{4}(0.8\pi)(0.2)^2+0.8\pi (0.2)^2)-(\frac{1}{12}(0.8)(0.2^2+02^2)+0.8(0.2)^2)=0.113$ kg*m$^2$