Chapter 17 - Planar Kinetics of a Rigid Body: Force and Acceleration - Section 17.1 - Mass Moment of Inertia - Problems - Page 420: 11

$I_{\circ}=1.36Kg\cdot m^2$

We can determine the required mass moment of inertia as follows: $I_{\circ}=\Sigma(I_G+md^2)$ We plug in the known values to obtain: $I_{\circ}=[\frac{1}{12}(3)(1.2)(1.2)^2+3(1.2)(0.2)^2]+[\frac{1}{12}(3)(0.4)(0.4)^2+3(0.4)(0.8)^2]$ This simplifies to: $I_{\circ}=1.36Kg\cdot m^2$