Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.6 - Instantaneous Center of Zero Velocity - Problems - Page 370: 86


$v_A=10.77in/s$ $21.8^{\circ}$ $v_B=14in/s$

Work Step by Step

The required velocity can be determined as follows: $r_{IC/B}=r_{O/IB}+r_{IC/O}$ $\implies r_{IC/B}=5+2=7in$ and $r_{IC/A}=\sqrt{(2)^2+(5)^2}=\sqrt{29}in$ We know that $v_A=\omega r_{IC/A}$ We plug in the known values to obtain: $v_A=2(\sqrt{29})=10.77in/s$ and $v_B=\omega r_{IC/B}$ We plug in the known values to obtain: $v_B=(2)(7)=14in/s \downarrow$ $\theta=tan^{-1}(\frac{2}{5})=21.8^{\circ}$
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