Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.6 - Instantaneous Center of Zero Velocity - Problems - Page 369: 85

Answer

$v_A=2ft/s\rightarrow$ $v_B=10ft/s\leftarrow$ yes, the cylinder slips on the conveyor.

Work Step by Step

The required velocity can be determined as follows: $r_{C/IC}=\frac{4}{6}=0.667ft$ We know that $v_A=\omega(r_{A/IC})$ $\implies v_A=\omega{r-r_{C/IC}}=6(1-0.667)=2ft/s \rightarrow$ and $v_B=\omega(r_{B/IC})=\omega(r+r_{C/IC})=6(1+0.667)=10ft/s \leftarrow$ As the velocity of the contact point A is not equal to that of the conveyor, therefore, the cylinder slips on the conveyer.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.