Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 16 - Planar Kinematics of a Rigid Body - Section 16.3 - Rotation about a Fixed Axis - Problems - Page 333: 19

Answer

Ans: $$ \begin{aligned} \omega_B =156 \mathrm{rad} / \mathrm{s} \end{aligned} $$

Work Step by Step

Angular velocity can be determine: $\omega_s=$ Angular velocity of the shaft $$ \begin{aligned} & \int d t=\int \frac{d \omega_S}{\alpha_S} \\ & \int_0^t d t=\int_1^{\omega_S} \frac{d \omega_S}{4 \omega_S^{3 / 4}} \\ & t_0^t=\left.\omega_S{ }^{1 / 4}\right|_1 ^{\mid \omega_s} \\ & t=\omega_S^{1 / 4}-1 \\ & \omega_S=(t+1)^4 \end{aligned} $$ $$ \begin{aligned} & t=4 \mathrm{~s}, \omega_s=? \\ & \omega_s=5^4=625 \mathrm{rad} / \mathrm{s} \end{aligned} $$ The brush is connected to the shaft so: $\omega_B=$ Angular velocity of the brush $$ \begin{aligned} & \omega_B r_B=\omega_s r_s \\ & \omega_B=\left(\frac{r_s}{r_B}\right) \omega_s=\left(\frac{0.25}{1}\right)(625)=156 \mathrm{rad} / \mathrm{s} \end{aligned} $$
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