Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.9 - Propulsion with Variable Mass - Problems - Page 312: 149

Answer

$F=m^{\prime}v^2$

Work Step by Step

We can determine the required force as follows: $\Sigma F_s=m\frac{dv}{dt}+\frac{dm_i}{dt}v_{D/i}$ As the car moves with constant speed, $\frac{dv}{dt}=0$ $\implies F=(m_{\circ}-m^{\prime}v)(0)+v(m^{\prime}v)$ This simplifies to: $F=m^{\prime}v^2$
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