Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.9 - Propulsion with Variable Mass - Problems - Page 312: 147



Work Step by Step

We can determine the required force as follows: $\Sigma F_s=m\frac{dv}{dt}+v_{D/i}\frac{dm_i}{dt}$ $\implies F-mgvt=0+v(mv)$ We plug in the known values to obtain: $F=2(9.81)(0.4t+(0.4)^2)$ This simplifies to: $F=(7.85t+0.320)N$
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