## Engineering Mechanics: Statics & Dynamics (14th Edition)

$45m/s;3375N$
The required speed and tension can be calculated as follows: $a=\frac{F_D}{m_1+m_2}$ $\implies a=\frac{9000}{2500+1500}$ $\implies a=2.25m/s^2$ Now $v=at$ Substituting the known values, we obtain: $v=2.25(20)$ $\implies v=45m/s$ The tension can be determined as $m_1a=F_D-T$ $\implies T=F_D-m_1a$ $\implies T=9000-2500(2.25)$ $\implies T=3375N$