Answer
$45m/s;3375N$
Work Step by Step
The required speed and tension can be calculated as follows:
$a=\frac{F_D}{m_1+m_2}$
$\implies a=\frac{9000}{2500+1500}$
$\implies a=2.25m/s^2$
Now $v=at$
Substituting the known values, we obtain:
$v=2.25(20)$
$\implies v=45m/s$
The tension can be determined as
$m_1a=F_D-T$
$\implies T=F_D-m_1a$
$\implies T=9000-2500(2.25)$
$\implies T=3375N$