Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 15 - Kinetics of a Particle: Impulse and Momentum - Section 15.2 - Principle of Linear Impulse and Momentum for a System of Particles - Fundamental Problems - Page 246: 4

Answer

$20m/s$

Work Step by Step

First, we calculate the impulse and then using it, we will determine the speed. $I=\frac{6000(2)}{2}+6000(6-2)=30000N.s$ Now the speed is given as $v=\frac{I}{m}$ We substitute the known values into the above equation $v=\frac{30000}{1500}=20m/s$
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