Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 14 - Kinetics of a Particle: Work and Energy - Section 14.4 - Power and Efficiency - Problems - Page 211: 59



Work Step by Step

The required power can be calculated as follows: The height of the steps is given as $H=nh=32(0.125)=4m$ and $W=nmg=32(150)(9.81)=47088N$ We know that $v_y=vsin\theta=(0.6)(\frac{4}{\sqrt{(32\times 0.25)^2+(4)^2}})=0.268m/s$ Now $P=Fv$ We plug in the known values to obtain: $P=(47088)(0.268)$ $\implies P=12.6KW$
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