Answer
$P=12.6KW$
Work Step by Step
The required power can be calculated as follows:
The height of the steps is given as
$H=nh=32(0.125)=4m$
and $W=nmg=32(150)(9.81)=47088N$
We know that
$v_y=vsin\theta=(0.6)(\frac{4}{\sqrt{(32\times 0.25)^2+(4)^2}})=0.268m/s$
Now $P=Fv$
We plug in the known values to obtain:
$P=(47088)(0.268)$
$\implies P=12.6KW$
