Answer
$P=0.0364hp$
Work Step by Step
We can determine the required power as follows:
$\Sigma F_y=ma_y=0$
$F(\frac{4}{5})-W=0$
$\implies F(\frac{4}{5})=10$
$\implies F=12.5lb$
Now $P=F\cdot v$
$\implies P=Fv(\frac{4}{5})$
We plug in the known values to obtain:
$P=12.5\times 2(\frac{4}{5})$
$\implies P=20lb\cdot ft/s=\frac{20}{550}hp=0.0364hp$
