Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 14 - Kinetics of a Particle: Work and Energy - Section 14.3 - Principle of Work and Energy for a System of Particles - Problems - Page 199: 18



Work Step by Step

The required maximum distance can be determined as follows: We know that $\Sigma U_{1-2}=12y-(2\times 15\times (t-4))=0$ As $t=\sqrt{y^2+(4)^2}$ $\implies 12y-30(\sqrt{y^2+(4)^2})=0$ $\implies 12y=30\sqrt{y^2+(4)^2}=0$ This simplifies to: $y=3.81ft$
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