Answer
$v_B=27.8ft/s$
Work Step by Step
The required speed can be determined as follows:
According to the principle of work and energy
$T_A+\Sigma U_{A-b}=T_B$
$\implies \frac{1}{2}mv_A+FS-Wh=\frac{1}{2}mv_B^2$
We plug in the known values to obtain:
$0+30(5.5)-10(4.5)=\frac{1}{2}(\frac{10}{32.2})v_B^2$
This simplifies to:
$v_B=27.8ft/s$
