Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 13 - Kinetics of a Particle: Force and Acceleration - Section 13.4 - Equations of Motion: Rectangular Coordinates - Problems - Page 130: 9



Work Step by Step

We can determine the required shortest time as follows: According to Newton's second law $\Sigma F_y=ma_y$ $\implies \Sigma F_y=m(0)=0$ $\implies N-W=0$ $\implies N=W=mg=10(9.81)=98.1N$ and $\Sigma F_x=ma_x$ $\implies \mu_s N=ma_x$ We plug in the known values to obtain: $0.2\times 98.1=10a$ $\implies a=1.962m/s^2$ As $v=v_{\circ}+at$ We plug in the known values to obtain: $4=0+1.962t$ This simplifies to: $t=2.04s$
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