Answer
$s=8.49m$
Work Step by Step
The required distance can be determined as follows:
According to Newton's second law
$\Sigma F_y=0$
$\implies N-W=0$
$\implies N=W=mg=10(9.81)=98.1N$
and $\Sigma F_x=ma_x$
$\implies \mu_k N=ma_x$
We plug in the known values to obtain:
$0.15\times 9.81=10a$
This simplifies to:
$a=1.4715m/s^2$
We know that
$v^2=v_{\circ}+2a(s-s_{\circ})$
We plug in the known values to obtain:
$0=(5)^2-[2\times 1.4715\times (s-0)]$
This simplifies to:
$s=8.49m$
