Answer
$a_t=17.1$ m/s$^2$
$\rho=6.44$ km
Work Step by Step
$a_t=50 \cos 70 = 17.1$ m/s$^2$
$a_n=50 \sin 70 = 46.98$ m/s$^2$
$a_n=\frac{v^2}{\rho}$
$46.98=\frac{550^2}{\rho}$
$\rho=6438.28$ m $=6.44$ km
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.7 - Curvilinear Motion: Normal and Tangential Components - Problems - Page 68: 136
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