Answer
$a=2.36$ m/s$^2$
Work Step by Step
$a_t=2$ m/s$^2$
$a_n=\frac{v^2}{\rho}=\frac{5^2}{20}=1.25$ m/s$^2$
$a=\sqrt{a_t^2+a_n^2}=\sqrt{2^2+1.25^2}=2.36$ ft/s$^2$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.7 - Curvilinear Motion: Normal and Tangential Components - Problems - Page 68: 131
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