Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.7 - Curvilinear Motion: Normal and Tangential Components - Problems - Page 65: 110

Answer

$v=63.2$ ft/s

Work Step by Step

Since the automobile is traveling at a constant speed, $a_t=0$. Thus, $a_n=a=5 ft/s^2$. $a_n=\frac{v^2}{\rho}$, we have $v=\sqrt{\rho a_n}=\sqrt{800(5)}=63.2$ ft/s
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