## Engineering Mechanics: Statics & Dynamics (14th Edition)

$v_{sp}=4.28$ m/s
We solve for the average speed as follows: $S_T=\frac{1}{4}(2\pi)(10)+15+\frac{1}{4}(2\pi(5))=38.56$ $v_{sp}=\frac{S_T}{t}=\frac{38.56}{2+4+3}=4.28$ m/s