Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.6 - Motion of a Projectile - Problems - Page 49: 74

Answer

$r = 11 i + 2 j + 21 k$ ft

Work Step by Step

$a=6t i + 12t^2 k$ $\int_0^v dv=\int_0^t (6ti + 12t^2 k) dt$ $v=3t^2 i + 4t^3 k$ $\int_{r_0}^r dr = \int_0^t (3t^2 i + 4t^3 k) dt$ $r-(3i+2j+5k)=t^3 i + t^4 k$ When $t=2$ s, $r = 11 i + 2 j + 21 k$ ft
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