Answer
The acceleration of the particle after 2 seconds is equal to 2 m/$s^2$
Work Step by Step
1. Using equation 12-2:
$$a = \frac {dv}{dt} $$
2. Substitute the expression and derivate:
$$a = \frac{d(0.5t^3 - 8t)}{dt} = 1.5t^2 - 8$$
3. At t =2 s:
$$a =1.5(2)^2 - 8 = -2 \space m/s^2$$
