## Engineering Mechanics: Statics & Dynamics (14th Edition)

1. Using equation 12-1: $$v = \frac{ds}{dt} \longrightarrow ds = v \space dt$$ $$\int_0^s ds = \int_0^tv \space dt$$ 2. Substitute the values and integrate: $$s = \int_0^t(4t - 3t^2)dt$$ $$s = \Big[2t^2 - t^3 \Big]_0^4 = (2(4)^2-(4)^3) - (2(0)^2 - (0))$$ $$s = -32 \space m \longrightarrow 32 \space m$$