Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 12 - Kinematics of a Particle - Section 12.10 - Relative-Motion of Two Particles using Translating Axes - Problems - Page 98: 199

Answer

$\Delta s_B = 1.33$

Work Step by Step

$2s_B+(s_B-s_C)=l$ $3s_B-s_C=l$ $3\Delta s_B - \Delta s_C=0$ Since $\Delta s_C=-4$, then $3 \Delta s_B = 04$ $\Delta s_B = -1.33$ ft $\Delta s_B = 1.33$ ft (towards the right)
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