Answer
$v_B=1.67$ m/s
Work Step by Step
$s_B+2(s_B-a)+s_A=l$
$3s_B+s_a=l+2a$
$3v_B+v_A=0$
$3v_B+5=0$
$v_B=-1.67$ m/s
$v_B=1.67$ m/s (negative sign indicates it is moving upwards)
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.10 - Relative-Motion of Two Particles using Translating Axes - Problems - Page 98: 198
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