Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 10 - Moments of Inertia - Section 10.8 - Mass Moment of Inertia - Problems - Page 571: 84

Answer

$I_z=R^2M$

Work Step by Step

We can find the moment of inertia of the ring about the z-axis as follows: $I_z=\int y^2 dm$ $\implies I_z=\int R^2 dm$ $\implies I_z=R^2\int dm$ As the total mass of the ring is M, therefore $M=\int dm$ $\implies I_z=R^2M$
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