Answer
\begin{array}{l}{\text { The order of magnitude for the previous algorithm would be the number of }} \\ {\text { times the printing of an element is performed, which is } n^{3} \text { . }}\end{array}
Work Step by Step
\begin{array}{l}{\text { The order of magnitude for the previous algorithm would be the number of }} \\ {\text { times the printing of an element is performed, which is } n^{3} \text { . }}\end{array}
