Answer
$524,288$ pages
Work Step by Step
1. The system needs $512 * 2 MB (1024 MB)$. $1 MB = 1,024kb$
2. We need 1024 MB measured in pages of 2 kb, so $x=1024*1024$ or $x=1024^{2}=1,048,576$ KiB
3. The number of pages is:
$$\frac{1,048,576}{2}=524,288$$
.