Computer Science: An Overview: Global Edition (12th Edition)

Published by Pearson Higher Education
ISBN 10: 1292061162
ISBN 13: 978-1-29206-116-0

Chapter 12 - Theory of Computation - Chapter Review Problems - Page 573: 49

Answer

$701$

Work Step by Step

To decrypt the message 1101 using RSA encryption with private keys \( n = 911 \) and \( d = 5 \), we'll use the following decryption formula: \[ M = C^d \mod n \] Where: - \( M \) is the decrypted message - \( C \) is the ciphertext (1101 in this case) - \( d \) is the private exponent - \( n \) is the modulus Plugging in the values: \[ M = 1101^5 \mod 911 \] We have: \[ 1101^5 = (911+190)^5 \] Now, taking the modulus: \[ 1101^5 \mod 911 = 190^5\mod 911 =(911\cdot 271,900,109+701) \mod 911 = 701 \] So, the decrypted message \( M \) is 701.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.