Answer
(a) $|W| = 1.48 \times 10^4 J $
(b) $Q_H = -4.58 \times 10^4J$
Work Step by Step
(a) From the coefficient of performance, we can find the energy is required each cycle to operate the refrigerator
$K = \frac{Q_C}{|W|}$
$|W| = \frac{Q_C}{K}$
$|W| = \frac{3.10 × 10^4 J}{2.10}$
$|W| = 1.48 \times 10^4 J $
(b) Heat discarded to the high-temperature reservoir,
$W = Q_C + Q_H$
$Q_H = -1.48 \times 10^4 J - 3.10 × 10^4 J$
$Q_H = -4.58 \times 10^4J$
