University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 20 - The Second Law of Thermodynamics - Problems - Exercises - Page 677: 20.7

Answer

(a) $𝜖 = 58.1 \%$ (b) $𝜖 = 59.5 \%$ $\Delta 𝜖 = 1.40 \%$

Work Step by Step

(a) $𝜖 = 1 - \frac{1}{r^{\gamma -1 }} $ $𝜖 = 1 - \frac{1}{8.80^{1.40 -1 }} $ $𝜖 = 1 - \frac{1}{8.80^{0.40}} $ $𝜖 = 58.1 \%$ (b) $𝜖 = 1 - \frac{1}{r^{\gamma -1 }} $ $𝜖 = 1 - \frac{1}{9.60^{1.40 -1 }} $ $𝜖 = 1 - \frac{1}{9.60^{0.40}} $ $𝜖 = 59.5 \%$ The difference in efficiency is $\Delta 𝜖 = 59.5 \% - 58.1 \% $ $\Delta 𝜖 = 1.40 \%$ The efficiency is increase by $1.40 \%$
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