Answer
(a) $Q_H = 492 J $
(b) $P = 212 W$
(c) $K = 5.4 $
Work Step by Step
(a) $Q_H = -(\frac{T_H}{T_C}) Q_C$
$Q_H = -(\frac{320K}{270K}) 415 J$
$Q_H = 492 J $
(b)$ |W| = |Q_H| − |Q_C|$
$ |W| = 492 J −415 J $
$ |W| = 77J$
$P = \frac{cycle \times W}{t}$
$P = \frac{165 \times 77J}{60 s}$
$P = 212 W$
(c) $K = \frac{|Q_C|}{|W|}$
$K = \frac{415 J}{77J|}$
$K = 5.4 $
