Answer
(a) $0.18\frac{KJ}{K}$
(b) $0.96\frac{KJ}{Kg.K}$
Work Step by Step
(a) The heat capacity of the object is
$C=\frac{Q}{\Delta T}$
We plug in the known values to obtain:
$C=\frac{2200}{12}$
$C=0.18\frac{KJ}{K}$
(b) The object's specific heat can be determined as
$c=\frac{C}{m}$
We plug in the known values to obtain:
$c=\frac{0.183}{0.190}$
$c=0.96\frac{KJ}{Kg.K}$
