Answer
$23.3^{\circ}C$
Work Step by Step
We know that
$c=\frac{Q}{m(T-T_{\circ})}$
This can be rearranged as:
$T=T_{\circ}+\frac{Q}{mC}$
We plug in the known values to obtain:
$T=22.5+\frac{79.3}{0.111(900)}=23.3^{\circ}C$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chaqpter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 567: 33
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
