Answer
$T=23.9^{\circ}C$
Work Step by Step
We can find the equilibrium temperature of the system as
$T=\frac{m_{pb}c_{pb}T_{pb}+m_wc_wT_w}{m_{pb}c_{pb}+m_wc_w}$
We plug in the known values to obtain:
$T=\frac{0.235(128)(84.2)+0.177(4186)(21.5)}{0.235(128)+0.177(4186)}$
$T=23.9^{\circ}C$