Answer
$0.93L$
Work Step by Step
We can find the required volume as follows:
$V=(\beta_{gas}-3\alpha_{tank})V_{\circ}\Delta t$
We plug in the known values to obtain:
$V=(9.5\times 10^{-4}-3\times 1.2\times 10^{-5})(51)(25-5)$
$V=0.93L$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chaqpter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 567: 21
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