Answer
Please see the work below.
Work Step by Step
We know that
$\Delta T=\frac{Q}{mc}$
$\implies \Delta T=\frac{mgh}{mc}$
$\Delta T=\frac{gh}{c}$
We plug in the known values to obtain:
$\Delta T=\frac{9.81(4.57)}{128}$
$\Delta T=0.350K$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 368: 40
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