Answer
(a) $37.63J$
(b) $0J$
Work Step by Step
(a) The required work done can be determined as
$W=mgh$
We plug in the known values to obtain:
$W=(3.2)(9.8)(1.2)$
$W=37.63J$
(b) We know that
$W=Fdcos\theta$
We plug in the known values to obtain:
$W=F(50m)cos(90^{\circ})$
$W=0J$
