Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 211: 16

(a) $0.55J$ (b) $0.28J$ (c) $-1.4J$

(a) We know that $W=F_xd_x$ We plug in the known values to obtain: $W=(2.2)(0.25)$ $W=0.55J$ (b) As $W=F_xd_x$ We plug in the known values to obtain: $W=(1.1)(0.25)$ $W=0.28J$ (c) We can find the required work done as follows: $W=F_xd_x+F_yd_y$ We plug in the known values to obtain: $W=(2.2)(-0.5)+(1.1)(-0.25)$ $W=-1.4J$