Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 211: 5

Answer

$m=4.36kg$

Work Step by Step

To find the work done by a constant force, use the formula $$W=Fdcos\theta$$ If the force of weight is $mg$ and $d$ is equal to $h$, the formula becomes $$W=mghcos\theta$$ Solving for $m$ yields $$m=\frac{W}{ghcos\theta}$$ Substituting known values of $W=201J$, $h=4.70m$, $g=9.80m/s^2$, and $\theta=0^{\circ}$ yields a mass of $$m=\frac{201J}{(9.80m/s^2)(4.70m)cos(0^{\circ})}=4.36kg$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.