Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 211: 12

Answer

$0.67KJ$

Work Step by Step

The work done on the crate can be calculated as follows: $W=Fdcos\theta$ We plug in the known values to obtain: $W=(115)(8.0)cos43.5^{\circ}$ $W=670J=0.67KJ$
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