Answer
$\theta=57.4^{\circ}$
Work Step by Step
To find the work done by a constant force, use the formula $$W=Fdcos\theta$$ Solving for the value of theta yields $$\theta=arccos(\frac{W}{Fd})$$ Substituting known values of $W=2.00\times 10^5J$, $F=2560N$, and $d=145m$ yields an angle of $$\theta=arccos(\frac{2.00\times 10^5J}{(2560J)(145m)})=57.4^{\circ}$$
