Answer
$27148Kg$
Work Step by Step
We are given the initial speed = $0\frac{m}{s}$
final speed =$155\frac{mi}{h}=\frac{155\times 1.6\times 10^3}{3600}=68.88\frac{m}{s}$
We know that
$v_f=v_i+at$
We plug in the known values to obtain:
$6.88=0+a(2)$
$a=34.44\frac{m}{s^2}$
We also know that
$F=ma$
This can be rearranged as:
$m=\frac{F}{a}$
We plug in the known values to obtain:
$m=\frac{9.35\times 10^5}{3.44}$
$m=27148Kg$
