Answer
(a) $2.2N$
(b) $1.4s$
(c) Please see the work below.
Work Step by Step
(a) We can find the magnitude of the force of gravity as
$F=mg$
We plug in the known values to obtain:
$F=(0.22Kg)(9.8m/s^2)$
$F=2.2N$
(b) We know that
$v=gt$
$\implies t=\frac{v}{g}$
We plug in the known values to obtain:
$t=\frac{14m/s}{9.8m/s^2}$
$t=1.4s$
(c) We know that
$mgt=(0.22Kg)(9.8m/s^2)(1.428s)$
$\implies mgt=3.08Kg.m/s$
Now $mv=(0.22Kg)(14m/s)$
$mv=3.08Kg.m/s$
Thus $mgt=mv$ and the dimensions of both equations are the same: $MLT^{-1}$
