Answer
$F=4.2\times 10^5 N$
Work Step by Step
Force is equal to $F=ma$. To find acceleration, use the kinematics equation relating acceleration, initial velocity, distance, and time, which is $$\Delta x=\frac{1}{2}a\Delta t^2+v_o\Delta t$$ Since the plane is at rest initially, $v_o=0.0m/s$. $$\Delta x=\frac{1}{2}a\Delta t^2$$ Solving for acceleration yields $$a=\frac{2\Delta x}{\Delta t^2}$$ Substituting known values of $\Delta x=1.5km=1500m$ and $\Delta t =35s$ yields an acceleration of $$a=\frac{2(1500m)}{(35s)^2}=2.4m/s^2$$ To find force, substitute known values of $m=1.70\times 10^{5} kg$ anad $a=2.4m/s^2$ to get a force of $$F=(1.70\times 10^5kg)(2.4m/s^2)=4.2\times 10^5 N$$
