Answer
$290Kg$
Work Step by Step
First of all, we convert the given force into the SI unit Newton:
$F=0.064oz$
$F=(0.064oz)(\frac{1lb}{16oz})(\frac{4.448N}{1lb})$
$F=0.0178N$
Now we convert the given velocity into SI units as well:
$\Delta v=(7900\frac{mi}{h})(\frac{1609m}{1mi})(\frac{1h}{3600s})$
$\Delta v=3530.86\frac{m}{s}$
$t=16000h=(1600h)(\frac{3600s}{1h})=5.76\times 10^7s$
$a=\frac{\Delta v}{t}$
$\implies a=\frac{3530.86}{5.76\times 10^7}=6.13\times 10^{-5}\frac{m}{s^2}$
Now we can find the required mass as follows:
$m=\frac{F}{a}$
We plug in the known values to obtain:
$m=\frac{0.0178}{6.13\times 10^{-5}}$
$m=290Kg$
