Answer
(a) $a=68.42\frac{m}{s^2}$
(b) $t=0.20s$
Work Step by Step
(a) We can find the required acceleration as follows:
$F=ma$
This can be rearranged as:
$a=\frac{F}{m}$
We plug in the known values to obtain:
$a=\frac{260,000}{3800}$
$a=68.42\frac{m}{s^2}$
(b) We know that
$s=v_it+\frac{1}{2}at^2$
We plug in the known values to obtain:
$1.46=0(t)+\frac{1}{2}(68.42)t^2$
This simplifies to:
$t=\sqrt{\frac{2\times 1.46}{68.42}}$
$t=0.20s$
